x+y = ln(exp(x) \* exp(y)) exp(a) = eml(a, 1) ln(a)=eml(1,eml(eml(1,a),1)) Plugg... | Hacker News

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		Charon77 22 days ago \| parent \| context \| favorite \| on: All elementary functions from a single binary oper... x+y = ln(exp(x) * exp(y)) exp(a) = eml(a, 1) ln(a)=eml(1,eml(eml(1,a),1)) Plugging those in is an excercise to the reader

freehorse 22 days ago | [–]

You use multiplication in the first line, which you have not expressed through eml yet.

Because of how exp and log turn addition into multiplication and vice versa, once you have the one, you get the other easily.

jcgrillo 22 days ago | [–]

might need to turn the paper sideways

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